Base | Representation |
---|---|
bin | 101110110001100000110111… |
… | …0000110100011101011111111 |
3 | 1222221201212202100022201111121 |
4 | 1131203001232012203223333 |
5 | 412411243111213244411 |
6 | 4015010110520131411 |
7 | 152442333552132400 |
oct | 13543015606435377 |
9 | 1887655670281447 |
10 | 411425354431231 |
11 | 10a1025708153a8 |
12 | 3a188ba6906b67 |
13 | 1487532409176a |
14 | 738514442b9a7 |
15 | 32871b7065571 |
hex | 176306e1a3aff |
411425354431231 has 6 divisors (see below), whose sum is σ = 478596840869040. Its totient is φ = 352650303798156.
The previous prime is 411425354431171. The next prime is 411425354431241. The reversal of 411425354431231 is 132134453524114.
It is not a de Polignac number, because 411425354431231 - 211 = 411425354429183 is a prime.
It is a super-2 number, since 2×4114253544312312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411425354431241) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4198217902311 + ... + 4198217902408.
It is an arithmetic number, because the mean of its divisors is an integer number (79766140144840).
Almost surely, 2411425354431231 is an apocalyptic number.
411425354431231 is a deficient number, since it is larger than the sum of its proper divisors (67171486437809).
411425354431231 is an equidigital number, since it uses as much as digits as its factorization.
411425354431231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8396435804733 (or 8396435804726 counting only the distinct ones).
The product of its digits is 691200, while the sum is 43.
The spelling of 411425354431231 in words is "four hundred eleven trillion, four hundred twenty-five billion, three hundred fifty-four million, four hundred thirty-one thousand, two hundred thirty-one".
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