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4114312040113 = 11715268005173
BaseRepresentation
bin111011110111110000000…
…110111000111010110001
3112120022202110222000022121
4323313300012320322301
51014402102340240423
612430031105434241
7603151326214102
oct73676006707261
915508673860277
104114312040113
1113469629832a0
1256546a93b981
1323ac9376c162
141031c30a23a9
157205191445d
hex3bdf01b8eb1

4114312040113 has 8 divisors (see below), whose sum is σ = 4551556470336. Its totient is φ = 3687603620400.

The previous prime is 4114312040009. The next prime is 4114312040131. The reversal of 4114312040113 is 3110402134114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4114312040113 - 29 = 4114312039601 is a prime.

It is a super-2 number, since 2×41143120401132 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114312040213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2634001806 + ... + 2634003367.

It is an arithmetic number, because the mean of its divisors is an integer number (568944558792).

Almost surely, 24114312040113 is an apocalyptic number.

It is an amenable number.

4114312040113 is a deficient number, since it is larger than the sum of its proper divisors (437244430223).

4114312040113 is a wasteful number, since it uses less digits than its factorization.

4114312040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5268005255.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 4114312040113 its reverse (3110402134114), we get a palindrome (7224714174227).

The spelling of 4114312040113 in words is "four trillion, one hundred fourteen billion, three hundred twelve million, forty thousand, one hundred thirteen".

Divisors: 1 11 71 781 5268005173 57948056903 374028367283 4114312040113