Base | Representation |
---|---|
bin | 111011110111110000000… |
… | …110111000111010110001 |
3 | 112120022202110222000022121 |
4 | 323313300012320322301 |
5 | 1014402102340240423 |
6 | 12430031105434241 |
7 | 603151326214102 |
oct | 73676006707261 |
9 | 15508673860277 |
10 | 4114312040113 |
11 | 13469629832a0 |
12 | 56546a93b981 |
13 | 23ac9376c162 |
14 | 1031c30a23a9 |
15 | 7205191445d |
hex | 3bdf01b8eb1 |
4114312040113 has 8 divisors (see below), whose sum is σ = 4551556470336. Its totient is φ = 3687603620400.
The previous prime is 4114312040009. The next prime is 4114312040131. The reversal of 4114312040113 is 3110402134114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4114312040113 - 29 = 4114312039601 is a prime.
It is a super-2 number, since 2×41143120401132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4114312040213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2634001806 + ... + 2634003367.
It is an arithmetic number, because the mean of its divisors is an integer number (568944558792).
Almost surely, 24114312040113 is an apocalyptic number.
It is an amenable number.
4114312040113 is a deficient number, since it is larger than the sum of its proper divisors (437244430223).
4114312040113 is a wasteful number, since it uses less digits than its factorization.
4114312040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5268005255.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 4114312040113 its reverse (3110402134114), we get a palindrome (7224714174227).
The spelling of 4114312040113 in words is "four trillion, one hundred fourteen billion, three hundred twelve million, forty thousand, one hundred thirteen".
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