4114413213331 has 4 divisors (see below), whose sum is σ = 4210097241592. Its totient is φ = 4018729185072.

The previous prime is 4114413213223. The next prime is 4114413213341. The reversal of 4114413213331 is 1333123144114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4114413213331 - 2¹⁹ = 4114412689043 is a prime.

It is a super-2 number, since 2×4114413213331² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4114413213293 and 4114413213302.

It is not an unprimeable number, because it can be changed into a prime (4114413213341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47842014066 + ... + 47842014151.

It is an arithmetic number, because the mean of its divisors is an integer number (1052524310398).

Almost surely, 2^{4114413213331} is an apocalyptic number.

4114413213331 is a deficient number, since it is larger than the sum of its proper divisors (95684028261).

4114413213331 is an equidigital number, since it uses as much as digits as its factorization.

4114413213331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95684028260.

The product of its digits is 10368, while the sum is 31.

Adding to 4114413213331 its reverse (1333123144114), we get a palindrome (5447536357445).

The spelling of 4114413213331 in words is "four trillion, one hundred fourteen billion, four hundred thirteen million, two hundred thirteen thousand, three hundred thirty-one".