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4114413213341 is a prime number
BaseRepresentation
bin111011110111110110001…
…000110101011010011101
3112120100000112100010220012
4323313312020311122131
51014402304240311331
612430045122133005
7603153665163554
oct73676610653235
915510015303805
104114413213341
111346a04aa6232
125654987b1165
1323acab703982
141031d26bad9b
157205a74b82b
hex3bdf623569d

4114413213341 has 2 divisors, whose sum is σ = 4114413213342. Its totient is φ = 4114413213340.

The previous prime is 4114413213223. The next prime is 4114413213347. The reversal of 4114413213341 is 1433123144114.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4094871969241 + 19541244100 = 2023579^2 + 139790^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114413213341 - 210 = 4114413212317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4114413213298 and 4114413213307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114413213347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057206606670 + 2057206606671.

It is an arithmetic number, because the mean of its divisors is an integer number (2057206606671).

Almost surely, 24114413213341 is an apocalyptic number.

It is an amenable number.

4114413213341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114413213341 is an equidigital number, since it uses as much as digits as its factorization.

4114413213341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 32.

Adding to 4114413213341 its reverse (1433123144114), we get a palindrome (5547536357455).

The spelling of 4114413213341 in words is "four trillion, one hundred fourteen billion, four hundred thirteen million, two hundred thirteen thousand, three hundred forty-one".