Base | Representation |
---|---|
bin | 1011111110110100101… |
… | …11101101000101110101 |
3 | 1110100122001222022121111 |
4 | 11333122113231011311 |
5 | 23221112444241323 |
6 | 513043053515021 |
7 | 41512644232243 |
oct | 5773227550565 |
9 | 1410561868544 |
10 | 411685540213 |
11 | 14965a833752 |
12 | 679547a2a71 |
13 | 2ca8b5b158c |
14 | 15cd6125793 |
15 | aa97750c0d |
hex | 5fda5ed175 |
411685540213 has 4 divisors (see below), whose sum is σ = 411690660480. Its totient is φ = 411680419948.
The previous prime is 411685540183. The next prime is 411685540237. The reversal of 411685540213 is 312045586114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 411685540213 - 213 = 411685532021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411685540813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2437573 + ... + 2600986.
It is an arithmetic number, because the mean of its divisors is an integer number (102922665120).
Almost surely, 2411685540213 is an apocalyptic number.
It is an amenable number.
411685540213 is a deficient number, since it is larger than the sum of its proper divisors (5120267).
411685540213 is an equidigital number, since it uses as much as digits as its factorization.
411685540213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5120266.
The product of its (nonzero) digits is 115200, while the sum is 40.
The spelling of 411685540213 in words is "four hundred eleven billion, six hundred eighty-five million, five hundred forty thousand, two hundred thirteen".
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