412000635643 has 4 divisors (see below), whose sum is σ = 412001961280. Its totient is φ = 411999310008.

The previous prime is 412000635569. The next prime is 412000635661. The reversal of 412000635643 is 346536000214.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 412000635643 - 2²¹ = 411998538491 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412000635599 and 412000635608.

It is not an unprimeable number, because it can be changed into a prime (412004635643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83446 + ... + 911572.

It is an arithmetic number, because the mean of its divisors is an integer number (103000490320).

Almost surely, 2^412000635643 is an apocalyptic number.

412000635643 is a deficient number, since it is larger than the sum of its proper divisors (1325637).

412000635643 is an equidigital number, since it uses as much as digits as its factorization.

412000635643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1325636.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 412000635643 its reverse (346536000214), we get a palindrome (758536635857).

The spelling of 412000635643 in words is "four hundred twelve billion, six hundred thirty-five thousand, six hundred forty-three".