4120010444131 has 4 divisors (see below), whose sum is σ = 4131815632000. Its totient is φ = 4108205256264.

The previous prime is 4120010444119. The next prime is 4120010444149. The reversal of 4120010444131 is 1314440100214.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4120010444131 is a prime.

It is a super-2 number, since 2×4120010444131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4120010444096 and 4120010444105.

It is not an unprimeable number, because it can be changed into a prime (4120010474131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5902593411 + ... + 5902594108.

It is an arithmetic number, because the mean of its divisors is an integer number (1032953908000).

Almost surely, 2^{4120010444131} is an apocalyptic number.

4120010444131 is a deficient number, since it is larger than the sum of its proper divisors (11805187869).

4120010444131 is a wasteful number, since it uses less digits than its factorization.

4120010444131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11805187868.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4120010444131 its reverse (1314440100214), we get a palindrome (5434450544345).

The spelling of 4120010444131 in words is "four trillion, one hundred twenty billion, ten million, four hundred forty-four thousand, one hundred thirty-one".