Base | Representation |
---|---|
bin | 111011111101000011110… |
… | …110100100001100000101 |
3 | 112120212110201110201000012 |
4 | 323331003312210030011 |
5 | 1020000241033424331 |
6 | 12432412444000005 |
7 | 603442511204546 |
oct | 73750366441405 |
9 | 15525421421005 |
10 | 4120012014341 |
11 | 13493184122a3 |
12 | 56659b830005 |
13 | 23b69162b482 |
14 | 1035a40d24cd |
15 | 7228703582b |
hex | 3bf43da4305 |
4120012014341 has 8 divisors (see below), whose sum is σ = 4152551347200. Its totient is φ = 4087474217568.
The previous prime is 4120012014329. The next prime is 4120012014383. The reversal of 4120012014341 is 1434102100214.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4120012014341 - 234 = 4102832145157 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4120012014241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5336585 + ... + 6059633.
It is an arithmetic number, because the mean of its divisors is an integer number (519068918400).
Almost surely, 24120012014341 is an apocalyptic number.
It is an amenable number.
4120012014341 is a deficient number, since it is larger than the sum of its proper divisors (32539332859).
4120012014341 is a wasteful number, since it uses less digits than its factorization.
4120012014341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768043.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 4120012014341 its reverse (1434102100214), we get a palindrome (5554114114555).
The spelling of 4120012014341 in words is "four trillion, one hundred twenty billion, twelve million, fourteen thousand, three hundred forty-one".
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