Base | Representation |
---|---|
bin | 1011111111011011100… |
… | …10000101100011001001 |
3 | 1110101110202210201201212 |
4 | 11333231302011203021 |
5 | 23222244333120431 |
6 | 513135250222505 |
7 | 41524010420402 |
oct | 5775562054311 |
9 | 1411422721655 |
10 | 412011223241 |
11 | 14980765a182 |
12 | 67a25884a35 |
13 | 2cb10c02427 |
14 | 15d274a29a9 |
15 | aab613472b |
hex | 5fedc858c9 |
412011223241 has 4 divisors (see below), whose sum is σ = 412028128512. Its totient is φ = 411994317972.
The previous prime is 412011223201. The next prime is 412011223277. The reversal of 412011223241 is 142322110214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142322110214 = 2 ⋅71161055107.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412011223241 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (412011223201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8416025 + ... + 8464838.
It is an arithmetic number, because the mean of its divisors is an integer number (103007032128).
Almost surely, 2412011223241 is an apocalyptic number.
It is an amenable number.
412011223241 is a deficient number, since it is larger than the sum of its proper divisors (16905271).
412011223241 is a wasteful number, since it uses less digits than its factorization.
412011223241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16905270.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 412011223241 its reverse (142322110214), we get a palindrome (554333333455).
The spelling of 412011223241 in words is "four hundred twelve billion, eleven million, two hundred twenty-three thousand, two hundred forty-one".
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