4120122314041 has 4 divisors (see below), whose sum is σ = 4123998253312. Its totient is φ = 4116246374772.

The previous prime is 4120122314029. The next prime is 4120122314117. The reversal of 4120122314041 is 1404132210214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4120122314041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4120122313997 and 4120122314015.

It is not an unprimeable number, because it can be changed into a prime (4120122314141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1937968041 + ... + 1937970166.

It is an arithmetic number, because the mean of its divisors is an integer number (1030999563328).

Almost surely, 2^{4120122314041} is an apocalyptic number.

It is an amenable number.

4120122314041 is a deficient number, since it is larger than the sum of its proper divisors (3875939271).

4120122314041 is a wasteful number, since it uses less digits than its factorization.

4120122314041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3875939270.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4120122314041 its reverse (1404132210214), we get a palindrome (5524254524255).

The spelling of 4120122314041 in words is "four trillion, one hundred twenty billion, one hundred twenty-two million, three hundred fourteen thousand, forty-one".