Base | Representation |
---|---|
bin | 111011111101001010011… |
… | …110110111101011101001 |
3 | 112120212202110202201101002 |
4 | 323331022132313223221 |
5 | 1020001003022240431 |
6 | 12432431500004345 |
7 | 603445331505215 |
oct | 73751236675351 |
9 | 15525673681332 |
10 | 4120123243241 |
11 | 1349375183205 |
12 | 566610b306b5 |
13 | 23b6ab6a3ca5 |
14 | 1035b4ba7945 |
15 | 72291ba73cb |
hex | 3bf4a7b7ae9 |
4120123243241 has 8 divisors (see below), whose sum is σ = 4162639219200. Its totient is φ = 4077608093568.
The previous prime is 4120123243153. The next prime is 4120123243259. The reversal of 4120123243241 is 1423423210214.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4120123243241 - 230 = 4119049501417 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4120123263241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18635060 + ... + 18854858.
It is an arithmetic number, because the mean of its divisors is an integer number (520329902400).
Almost surely, 24120123243241 is an apocalyptic number.
It is an amenable number.
4120123243241 is a deficient number, since it is larger than the sum of its proper divisors (42515975959).
4120123243241 is a wasteful number, since it uses less digits than its factorization.
4120123243241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 413143.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4120123243241 its reverse (1423423210214), we get a palindrome (5543546453455).
The spelling of 4120123243241 in words is "four trillion, one hundred twenty billion, one hundred twenty-three million, two hundred forty-three thousand, two hundred forty-one".
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