412013033035 has 4 divisors (see below), whose sum is σ = 494415639648. Its totient is φ = 329610426424.

The previous prime is 412013032993. The next prime is 412013033053. The reversal of 412013033035 is 530330310214.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 412013033035 - 2¹¹ = 412013030987 is a prime.

It is a super-2 number, since 2×412013033035² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41201303299 + ... + 41201303308.

It is an arithmetic number, because the mean of its divisors is an integer number (123603909912).

Almost surely, 2^412013033035 is an apocalyptic number.

412013033035 is a deficient number, since it is larger than the sum of its proper divisors (82402606613).

412013033035 is an equidigital number, since it uses as much as digits as its factorization.

412013033035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82402606612.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 412013033035 its reverse (530330310214), we get a palindrome (942343343249).

The spelling of 412013033035 in words is "four hundred twelve billion, thirteen million, thirty-three thousand, thirty-five".