4120142826343 has 4 divisors (see below), whose sum is σ = 4120175188360. Its totient is φ = 4120110464328.

The previous prime is 4120142826313. The next prime is 4120142826391. The reversal of 4120142826343 is 3436282410214.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4120142826343 - 2⁹ = 4120142825831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4120142826296 and 4120142826305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4120142826313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15989280 + ... + 16244917.

It is an arithmetic number, because the mean of its divisors is an integer number (1030043797090).

Almost surely, 2^{4120142826343} is an apocalyptic number.

4120142826343 is a deficient number, since it is larger than the sum of its proper divisors (32362017).

4120142826343 is a wasteful number, since it uses less digits than its factorization.

4120142826343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32362016.

The product of its (nonzero) digits is 221184, while the sum is 40.

The spelling of 4120142826343 in words is "four trillion, one hundred twenty billion, one hundred forty-two million, eight hundred twenty-six thousand, three hundred forty-three".