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412020202213 = 3323123990431
BaseRepresentation
bin1011111111011100101…
…00010101101011100101
31110101111101200220120101
411333232110111223211
523222304132432323
6513140210504101
741524146635224
oct5775624255345
91411441626511
10412020202213
11149811732214
1267a28895031
132cb12a27329
1415d2875ccbb
15aab6d09dad
hex5fee515ae5

412020202213 has 4 divisors (see below), whose sum is σ = 412144195968. Its totient is φ = 411896208460.

The previous prime is 412020202199. The next prime is 412020202241. The reversal of 412020202213 is 312202020214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412020202213 - 237 = 274581248741 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412020202613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61991893 + ... + 61998538.

It is an arithmetic number, because the mean of its divisors is an integer number (103036048992).

Almost surely, 2412020202213 is an apocalyptic number.

It is an amenable number.

412020202213 is a deficient number, since it is larger than the sum of its proper divisors (123993755).

412020202213 is a wasteful number, since it uses less digits than its factorization.

412020202213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123993754.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 412020202213 its reverse (312202020214), we get a palindrome (724222222427).

The spelling of 412020202213 in words is "four hundred twelve billion, twenty million, two hundred two thousand, two hundred thirteen".

Divisors: 1 3323 123990431 412020202213