Base | Representation |
---|---|
bin | 1011111111011100101… |
… | …00011110111111010101 |
3 | 1110101111101202211212112 |
4 | 11333232110132333111 |
5 | 23222304140142331 |
6 | 513140211400405 |
7 | 41524150154333 |
oct | 5775624367725 |
9 | 1411441684775 |
10 | 412020240341 |
11 | 149811758926 |
12 | 67a288b3105 |
13 | 2cb12a3b7a8 |
14 | 15d2876cb53 |
15 | aab6d1632b |
hex | 5fee51efd5 |
412020240341 has 4 divisors (see below), whose sum is σ = 412068309132. Its totient is φ = 411972171552.
The previous prime is 412020240263. The next prime is 412020240353. The reversal of 412020240341 is 143042020214.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 280127791441 + 131892448900 = 529271^2 + 363170^2 .
It is a cyclic number.
It is not a de Polignac number, because 412020240341 - 210 = 412020239317 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412020240391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24021536 + ... + 24038681.
It is an arithmetic number, because the mean of its divisors is an integer number (103017077283).
Almost surely, 2412020240341 is an apocalyptic number.
It is an amenable number.
412020240341 is a deficient number, since it is larger than the sum of its proper divisors (48068791).
412020240341 is an equidigital number, since it uses as much as digits as its factorization.
412020240341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48068790.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 412020240341 its reverse (143042020214), we get a palindrome (555062260555).
The spelling of 412020240341 in words is "four hundred twelve billion, twenty million, two hundred forty thousand, three hundred forty-one".
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