Base | Representation |
---|---|
bin | 101110110101110110000000… |
… | …1100101101101000000000101 |
3 | 2000000211210000110022102212121 |
4 | 1131223230001211231000011 |
5 | 413001021023242132240 |
6 | 4020143342003045541 |
7 | 152533333635623242 |
oct | 13553540145550005 |
9 | 2000753013272777 |
10 | 412020534333445 |
11 | 10a311a22307104 |
12 | 3a26440b3708b1 |
13 | 148b94a622b8ab |
14 | 73a5c864805c9 |
15 | 32978edb6604a |
hex | 176bb0196d005 |
412020534333445 has 16 divisors (see below), whose sum is σ = 494921421991152. Its totient is φ = 329285251722240.
The previous prime is 412020534333437. The next prime is 412020534333563. The reversal of 412020534333445 is 544333435020214.
It can be written as a sum of positive squares in 8 ways, for example, as 208164904382241 + 203855629951204 = 14427921^2 + 14277802^2 .
It is not a de Polignac number, because 412020534333445 - 23 = 412020534333437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299876749 + ... + 301247581.
It is an arithmetic number, because the mean of its divisors is an integer number (30932588874447).
Almost surely, 2412020534333445 is an apocalyptic number.
It is an amenable number.
412020534333445 is a deficient number, since it is larger than the sum of its proper divisors (82900887657707).
412020534333445 is a wasteful number, since it uses less digits than its factorization.
412020534333445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1431192.
The product of its (nonzero) digits is 2073600, while the sum is 43.
Adding to 412020534333445 its reverse (544333435020214), we get a palindrome (956353969353659).
The spelling of 412020534333445 in words is "four hundred twelve trillion, twenty billion, five hundred thirty-four million, three hundred thirty-three thousand, four hundred forty-five".
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