412020534333533 has 4 divisors (see below), whose sum is σ = 429934470608928. Its totient is φ = 394106598058140.

The previous prime is 412020534333437. The next prime is 412020534333563. The reversal of 412020534333533 is 335333435020214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412020534333533 - 2²⁸ = 412020265898077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412020534333563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8956968137663 + ... + 8956968137708.

It is an arithmetic number, because the mean of its divisors is an integer number (107483617652232).

Almost surely, 2^{412020534333533} is an apocalyptic number.

It is an amenable number.

412020534333533 is a deficient number, since it is larger than the sum of its proper divisors (17913936275395).

412020534333533 is a wasteful number, since it uses less digits than its factorization.

412020534333533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17913936275394.

The product of its (nonzero) digits is 1166400, while the sum is 41.

Adding to 412020534333533 its reverse (335333435020214), we get a palindrome (747353969353747).

The spelling of 412020534333533 in words is "four hundred twelve trillion, twenty billion, five hundred thirty-four million, three hundred thirty-three thousand, five hundred thirty-three".