Base | Representation |
---|---|
bin | 111011111101010000011… |
… | …111011000100001001011 |
3 | 112120220000111102202221201 |
4 | 323331100133120201023 |
5 | 1020001204323303120 |
6 | 12432445500245031 |
7 | 603450664332304 |
oct | 73752037304113 |
9 | 15526014382851 |
10 | 4120224041035 |
11 | 134941706a073 |
12 | 56663a840777 |
13 | 23b6c653695b |
14 | 1035c43257ab |
15 | 7229a96840a |
hex | 3bf507d884b |
4120224041035 has 32 divisors (see below), whose sum is σ = 5099364990720. Its totient is φ = 3194082460800.
The previous prime is 4120224041027. The next prime is 4120224041159. The reversal of 4120224041035 is 5301404220214.
It is not a de Polignac number, because 4120224041035 - 23 = 4120224041027 is a prime.
It is a super-2 number, since 2×41202240410352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4120224040994 and 4120224041012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16179040 + ... + 16431730.
It is an arithmetic number, because the mean of its divisors is an integer number (159355155960).
Almost surely, 24120224041035 is an apocalyptic number.
4120224041035 is a deficient number, since it is larger than the sum of its proper divisors (979140949685).
4120224041035 is a wasteful number, since it uses less digits than its factorization.
4120224041035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 253339.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 4120224041035 its reverse (5301404220214), we get a palindrome (9421628261249).
The spelling of 4120224041035 in words is "four trillion, one hundred twenty billion, two hundred twenty-four million, forty-one thousand, thirty-five".
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