Base | Representation |
---|---|
bin | 10010101111001001001010… |
… | …00001111101011100010011 |
3 | 12101212220012010101000200021 |
4 | 21113210211001331130103 |
5 | 20400024143042310311 |
6 | 223344014322204311 |
7 | 11451522660040114 |
oct | 1127444501753423 |
9 | 171786163330607 |
10 | 41202242541331 |
11 | 12145855857703 |
12 | 475532b7b3697 |
13 | 19cb47c65a2b1 |
14 | a262b079620b |
15 | 4b6b71729171 |
hex | 25792507d713 |
41202242541331 has 4 divisors (see below), whose sum is σ = 41202256531464. Its totient is φ = 41202228551200.
The previous prime is 41202242541311. The next prime is 41202242541353. The reversal of 41202242541331 is 13314524220214.
41202242541331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 41202242541331 - 29 = 41202242540819 is a prime.
It is a super-2 number, since 2×412022425413312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41202242541311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 672550 + ... + 9102571.
It is an arithmetic number, because the mean of its divisors is an integer number (10300564132866).
Almost surely, 241202242541331 is an apocalyptic number.
41202242541331 is a deficient number, since it is larger than the sum of its proper divisors (13990133).
41202242541331 is an equidigital number, since it uses as much as digits as its factorization.
41202242541331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13990132.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 41202242541331 its reverse (13314524220214), we get a palindrome (54516766761545).
The spelling of 41202242541331 in words is "forty-one trillion, two hundred two billion, two hundred forty-two million, five hundred forty-one thousand, three hundred thirty-one".
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