Base | Representation |
---|---|
bin | 111011111101010111100… |
… | …011011101111111010111 |
3 | 112120220022202102210011112 |
4 | 323331113203131333113 |
5 | 1020001430143140120 |
6 | 12432505332325235 |
7 | 603453633554006 |
oct | 73752743357727 |
9 | 15526282383145 |
10 | 4120342552535 |
11 | 1349477a54560 |
12 | 56667247381b |
13 | 23b714c5c1c1 |
14 | 1035d5d74c3d |
15 | 722a6077bc5 |
hex | 3bf578ddfd7 |
4120342552535 has 16 divisors (see below), whose sum is σ = 5393942547840. Its totient is φ = 2996590782240.
The previous prime is 4120342552519. The next prime is 4120342552553. The reversal of 4120342552535 is 5352552430214.
It is not a de Polignac number, because 4120342552535 - 24 = 4120342552519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4120342552492 and 4120342552501.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13622576 + ... + 13921754.
It is an arithmetic number, because the mean of its divisors is an integer number (337121409240).
Almost surely, 24120342552535 is an apocalyptic number.
4120342552535 is a deficient number, since it is larger than the sum of its proper divisors (1273599995305).
4120342552535 is a wasteful number, since it uses less digits than its factorization.
4120342552535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 549598.
The product of its (nonzero) digits is 720000, while the sum is 41.
Adding to 4120342552535 its reverse (5352552430214), we get a palindrome (9472894982749).
The spelling of 4120342552535 in words is "four trillion, one hundred twenty billion, three hundred forty-two million, five hundred fifty-two thousand, five hundred thirty-five".
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