Base | Representation |
---|---|
bin | 101110110101111111101100… |
… | …1001110100101001100101011 |
3 | 2000000220202200212211101101020 |
4 | 1131223333121032211030223 |
5 | 413001341121444120021 |
6 | 4020201101425423523 |
7 | 152535001215220041 |
oct | 13553773116451453 |
9 | 2000822625741336 |
10 | 412041332020011 |
11 | 10a31a825036921 |
12 | 3a26845449aba3 |
13 | 148bb43bc593c5 |
14 | 73a6c9a68c391 |
15 | 329821994d7c6 |
hex | 176bfd93a532b |
412041332020011 has 4 divisors (see below), whose sum is σ = 549388442693352. Its totient is φ = 274694221346672.
The previous prime is 412041332019917. The next prime is 412041332020033. The reversal of 412041332020011 is 110020233140214.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 412041332020011 - 219 = 412041331495723 is a prime.
It is not an unprimeable number, because it can be changed into a prime (412041332020051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68673555336666 + ... + 68673555336671.
It is an arithmetic number, because the mean of its divisors is an integer number (137347110673338).
Almost surely, 2412041332020011 is an apocalyptic number.
412041332020011 is a deficient number, since it is larger than the sum of its proper divisors (137347110673341).
412041332020011 is a wasteful number, since it uses less digits than its factorization.
412041332020011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137347110673340.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 412041332020011 its reverse (110020233140214), we get a palindrome (522061565160225).
The spelling of 412041332020011 in words is "four hundred twelve trillion, forty-one billion, three hundred thirty-two million, twenty thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •