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412050115 = 582410023
BaseRepresentation
bin11000100011110…
…110001011000011
31001201100022111101
4120203312023003
51320441100430
6104515355231
713132240201
oct3043661303
91051308441
10412050115
111a1656394
12b5bb2b17
13674a0349
143ca20071
1526293dca
hex188f62c3

412050115 has 4 divisors (see below), whose sum is σ = 494460144. Its totient is φ = 329640088.

The previous prime is 412050077. The next prime is 412050157. The reversal of 412050115 is 511050214.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511050214 = 2255525107.

It is a cyclic number.

It is not a de Polignac number, because 412050115 - 211 = 412048067 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412050092 and 412050101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41205007 + ... + 41205016.

It is an arithmetic number, because the mean of its divisors is an integer number (123615036).

Almost surely, 2412050115 is an apocalyptic number.

412050115 is a deficient number, since it is larger than the sum of its proper divisors (82410029).

412050115 is an equidigital number, since it uses as much as digits as its factorization.

412050115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82410028.

The product of its (nonzero) digits is 200, while the sum is 19.

The square root of 412050115 is about 20299.0175870656. The cubic root of 412050115 is about 744.1320552922.

Subtracting 412050115 from its reverse (511050214), we obtain a palindrome (99000099).

The spelling of 412050115 in words is "four hundred twelve million, fifty thousand, one hundred fifteen".

Divisors: 1 5 82410023 412050115