Base | Representation |
---|---|
bin | 1011111111100001000… |
… | …00110000110001011101 |
3 | 1110101120221222002221111 |
4 | 11333300200300301131 |
5 | 23222343043411331 |
6 | 513144003502021 |
7 | 41525104552261 |
oct | 5776040606135 |
9 | 1411527862844 |
10 | 412057013341 |
11 | 149830494a36 |
12 | 67a39087911 |
13 | 2cb1a54556c |
14 | 15d2d5c20a1 |
15 | aaba17bdb1 |
hex | 5ff0830c5d |
412057013341 has 4 divisors (see below), whose sum is σ = 426265875900. Its totient is φ = 397848150784.
The previous prime is 412057013323. The next prime is 412057013393. The reversal of 412057013341 is 143310750214.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 222174593316 + 189882420025 = 471354^2 + 435755^2 .
It is a cyclic number.
It is not a de Polignac number, because 412057013341 - 211 = 412057011293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412057013311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7104431236 + ... + 7104431293.
It is an arithmetic number, because the mean of its divisors is an integer number (106566468975).
Almost surely, 2412057013341 is an apocalyptic number.
It is an amenable number.
412057013341 is a deficient number, since it is larger than the sum of its proper divisors (14208862559).
412057013341 is a wasteful number, since it uses less digits than its factorization.
412057013341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14208862558.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 412057013341 its reverse (143310750214), we get a palindrome (555367763555).
The spelling of 412057013341 in words is "four hundred twelve billion, fifty-seven million, thirteen thousand, three hundred forty-one".
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