Base | Representation |
---|---|
bin | 111011111110011000100… |
… | …011101111001100001111 |
3 | 112121000010202120110201002 |
4 | 323332120203233030033 |
5 | 1020011143341021111 |
6 | 12433205451410515 |
7 | 603522645454142 |
oct | 73763043571417 |
9 | 15530122513632 |
10 | 4121433142031 |
11 | 1349987621597 |
12 | 566917753a3b |
13 | 23b859b9672a |
14 | 10369ab44059 |
15 | 7231bba063b |
hex | 3bf988ef30f |
4121433142031 has 16 divisors (see below), whose sum is σ = 4263675413088. Its totient is φ = 3982179801600.
The previous prime is 4121433142009. The next prime is 4121433142037. The reversal of 4121433142031 is 1302413341214.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4121433142031 is a prime.
It is a super-2 number, since 2×41214331420312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4121433141985 and 4121433142003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4121433142037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1442510 + ... + 3213051.
It is an arithmetic number, because the mean of its divisors is an integer number (266479713318).
Almost surely, 24121433142031 is an apocalyptic number.
4121433142031 is a deficient number, since it is larger than the sum of its proper divisors (142242271057).
4121433142031 is a wasteful number, since it uses less digits than its factorization.
4121433142031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4655882.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4121433142031 its reverse (1302413341214), we get a palindrome (5423846483245).
The spelling of 4121433142031 in words is "four trillion, one hundred twenty-one billion, four hundred thirty-three million, one hundred forty-two thousand, thirty-one".
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