Base | Representation |
---|---|
bin | 111011111111001001011… |
… | …111011110110110110111 |
3 | 112121002020222100222020011 |
4 | 323333021133132312313 |
5 | 1020014334023011020 |
6 | 12433423135521051 |
7 | 603552204541150 |
oct | 73771137366667 |
9 | 15532228328204 |
10 | 4122254110135 |
11 | 134a268a84027 |
12 | 566b06689187 |
13 | 23b95acab585 |
14 | 103737baa927 |
15 | 72368cba35a |
hex | 3bfc97dedb7 |
4122254110135 has 16 divisors (see below), whose sum is σ = 5656437997056. Its totient is φ = 2825158066848.
The previous prime is 4122254110081. The next prime is 4122254110159. The reversal of 4122254110135 is 5310114522214.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4122254110135 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4122254110097 and 4122254110106.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31819137 + ... + 31948426.
It is an arithmetic number, because the mean of its divisors is an integer number (353527374816).
Almost surely, 24122254110135 is an apocalyptic number.
4122254110135 is a deficient number, since it is larger than the sum of its proper divisors (1534183886921).
4122254110135 is a wasteful number, since it uses less digits than its factorization.
4122254110135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63769422.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 4122254110135 its reverse (5310114522214), we get a palindrome (9432368632349).
The spelling of 4122254110135 in words is "four trillion, one hundred twenty-two billion, two hundred fifty-four million, one hundred ten thousand, one hundred thirty-five".
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