Base | Representation |
---|---|
bin | 101110110111010101011101… |
… | …1010001101001011110011101 |
3 | 2000001120101002210000201210020 |
4 | 1131232222323101221132131 |
5 | 413012400322323214323 |
6 | 4020421441505302353 |
7 | 152554211333454210 |
oct | 13556527321513635 |
9 | 2001511083021706 |
10 | 412225513101213 |
11 | 10a3909494a3209 |
12 | 3a2980963349b9 |
13 | 14902911b843a6 |
14 | 73b1b6d897777 |
15 | 329cde924aae3 |
hex | 176eabb46979d |
412225513101213 has 16 divisors (see below), whose sum is σ = 665103348869760. Its totient is φ = 221701116289536.
The previous prime is 412225513101167. The next prime is 412225513101223. The reversal of 412225513101213 is 312101315522214.
It is not a de Polignac number, because 412225513101213 - 210 = 412225513100189 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412225513101223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 577346656648 + ... + 577346657361.
It is an arithmetic number, because the mean of its divisors is an integer number (41568959304360).
Almost surely, 2412225513101213 is an apocalyptic number.
It is an amenable number.
412225513101213 is a deficient number, since it is larger than the sum of its proper divisors (252877835768547).
412225513101213 is a wasteful number, since it uses less digits than its factorization.
412225513101213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1154693314036.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 412225513101213 its reverse (312101315522214), we get a palindrome (724326828623427).
The spelling of 412225513101213 in words is "four hundred twelve trillion, two hundred twenty-five billion, five hundred thirteen million, one hundred one thousand, two hundred thirteen".
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