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41224133113 = 147672791639
BaseRepresentation
bin100110011001001001…
…100101100111111001
310221101222110221102221
4212121021211213321
51133411334224423
630534344124041
72656400231002
oct463111454771
9127358427387
1041224133113
1116534a483a9
127ba5a66621
133b6c876497
141dd0dc01a9
1511141dce5d
hex9992659f9

41224133113 has 4 divisors (see below), whose sum is σ = 41226939520. Its totient is φ = 41221326708.

The previous prime is 41224133089. The next prime is 41224133117. The reversal of 41224133113 is 31133142214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41224133113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41224133117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1381053 + ... + 1410586.

It is an arithmetic number, because the mean of its divisors is an integer number (10306734880).

Almost surely, 241224133113 is an apocalyptic number.

It is an amenable number.

41224133113 is a deficient number, since it is larger than the sum of its proper divisors (2806407).

41224133113 is a wasteful number, since it uses less digits than its factorization.

41224133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2806406.

The product of its digits is 1728, while the sum is 25.

Adding to 41224133113 its reverse (31133142214), we get a palindrome (72357275327).

The spelling of 41224133113 in words is "forty-one billion, two hundred twenty-four million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 14767 2791639 41224133113