Base | Representation |
---|---|
bin | 1011111111111110011… |
… | …11000001001001000010 |
3 | 1110102020011202100102112 |
4 | 11333333033001021002 |
5 | 23223344312120114 |
6 | 513224310015322 |
7 | 41534164226354 |
oct | 5777717011102 |
9 | 1412204670375 |
10 | 412304020034 |
11 | 1499479637a5 |
12 | 67aa7947542 |
13 | 2cb5977a67a |
14 | 15d5431d0d4 |
15 | aad1bbe13e |
hex | 5fff3c1242 |
412304020034 has 4 divisors (see below), whose sum is σ = 618456030054. Its totient is φ = 206152010016.
The previous prime is 412304020021. The next prime is 412304020057. The reversal of 412304020034 is 430020403214.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 220192747009 + 192111273025 = 469247^2 + 438305^2 .
It is a super-2 number, since 2×4123040200342 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 412304019991 and 412304020009.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 103076005007 + ... + 103076005010.
Almost surely, 2412304020034 is an apocalyptic number.
412304020034 is a deficient number, since it is larger than the sum of its proper divisors (206152010020).
412304020034 is a wasteful number, since it uses less digits than its factorization.
412304020034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206152010019.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 412304020034 its reverse (430020403214), we get a palindrome (842324423248).
The spelling of 412304020034 in words is "four hundred twelve billion, three hundred four million, twenty thousand, thirty-four".
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