4123043210131 has 4 divisors (see below), whose sum is σ = 4218927935992. Its totient is φ = 4027158484272.

The previous prime is 4123043210119. The next prime is 4123043210183. The reversal of 4123043210131 is 1310123403214.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4123043210131 - 2¹³ = 4123043201939 is a prime.

It is a super-2 number, since 2×4123043210131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4123043210096 and 4123043210105.

It is not an unprimeable number, because it can be changed into a prime (4123046210131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47942362866 + ... + 47942362951.

It is an arithmetic number, because the mean of its divisors is an integer number (1054731983998).

Almost surely, 2^{4123043210131} is an apocalyptic number.

4123043210131 is a deficient number, since it is larger than the sum of its proper divisors (95884725861).

4123043210131 is an equidigital number, since it uses as much as digits as its factorization.

4123043210131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95884725860.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4123043210131 its reverse (1310123403214), we get a palindrome (5433166613345).

The spelling of 4123043210131 in words is "four trillion, one hundred twenty-three billion, forty-three million, two hundred ten thousand, one hundred thirty-one".