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4123302442113 = 31374434147371
BaseRepresentation
bin111100000000000111111…
…110100011010010000001
3112121011222000222202100110
4330000013332203102001
51020024010411121423
612434115145141533
7603620164321461
oct74000776432201
915534860882313
104123302442113
11134a756809398
1256715978a8a9
1323ba9723b85a
141037d70d9ba1
15723cad47193
hex3c007fa3481

4123302442113 has 4 divisors (see below), whose sum is σ = 5497736589488. Its totient is φ = 2748868294740.

The previous prime is 4123302442027. The next prime is 4123302442141. The reversal of 4123302442113 is 3112442033214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4123302442113 - 28 = 4123302441857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4123302442013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 687217073683 + ... + 687217073688.

It is an arithmetic number, because the mean of its divisors is an integer number (1374434147372).

Almost surely, 24123302442113 is an apocalyptic number.

It is an amenable number.

4123302442113 is a deficient number, since it is larger than the sum of its proper divisors (1374434147375).

4123302442113 is a wasteful number, since it uses less digits than its factorization.

4123302442113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1374434147374.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 4123302442113 its reverse (3112442033214), we get a palindrome (7235744475327).

The spelling of 4123302442113 in words is "four trillion, one hundred twenty-three billion, three hundred two million, four hundred forty-two thousand, one hundred thirteen".

Divisors: 1 3 1374434147371 4123302442113