Base | Representation |
---|---|
bin | 10010110000000010111001… |
… | …10001000111001101000001 |
3 | 12101222212012120010000202220 |
4 | 21120001130301013031001 |
5 | 20401031140024420113 |
6 | 223410142353201253 |
7 | 11454001120463166 |
oct | 1130013461071501 |
9 | 171885176100686 |
10 | 41233242420033 |
11 | 12157a13441374 |
12 | 475b341560229 |
13 | 1a0137cc192a1 |
14 | a279b191a06d |
15 | 4b788800d523 |
hex | 25805cc47341 |
41233242420033 has 32 divisors (see below), whose sum is σ = 56930124246912. Its totient is φ = 26528538624000.
The previous prime is 41233242419953. The next prime is 41233242420047. The reversal of 41233242420033 is 33002424233214.
It is not a de Polignac number, because 41233242420033 - 213 = 41233242411841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41233242419976 and 41233242420003.
It is not an unprimeable number, because it can be changed into a prime (41233242422033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 445633 + ... + 9092033.
It is an arithmetic number, because the mean of its divisors is an integer number (1779066382716).
Almost surely, 241233242420033 is an apocalyptic number.
It is an amenable number.
41233242420033 is a deficient number, since it is larger than the sum of its proper divisors (15696881826879).
41233242420033 is a wasteful number, since it uses less digits than its factorization.
41233242420033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8646865.
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 41233242420033 its reverse (33002424233214), we get a palindrome (74235666653247).
The spelling of 41233242420033 in words is "forty-one trillion, two hundred thirty-three billion, two hundred forty-two million, four hundred twenty thousand, thirty-three".
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