Base | Representation |
---|---|
bin | 111100000001001100100… |
… | …011110010011001010010 |
3 | 112121021221020001220011210 |
4 | 330001030203302121102 |
5 | 1020033334440212114 |
6 | 12434425250520550 |
7 | 603660535341255 |
oct | 74011443623122 |
9 | 15537836056153 |
10 | 4124453054034 |
11 | 1350197252135 |
12 | 56741ab96156 |
13 | 23bc1b730301 |
14 | 1038a5c5109c |
15 | 72446d79259 |
hex | 3c04c8f2652 |
4124453054034 has 16 divisors (see below), whose sum is σ = 8249353594272. Its totient is φ = 1374743103648.
The previous prime is 4124453054017. The next prime is 4124453054039. The reversal of 4124453054034 is 4304503544214.
It is a super-3 number, since 3×41244530540343 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 4124453053983 and 4124453054001.
It is not an unprimeable number, because it can be changed into a prime (4124453054039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18525379 + ... + 18746694.
It is an arithmetic number, because the mean of its divisors is an integer number (515584599642).
Almost surely, 24124453054034 is an apocalyptic number.
4124453054034 is an abundant number, since it is smaller than the sum of its proper divisors (4124900540238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4124453054034 is a wasteful number, since it uses less digits than its factorization.
4124453054034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37290521.
The product of its (nonzero) digits is 460800, while the sum is 39.
Adding to 4124453054034 its reverse (4304503544214), we get a palindrome (8428956598248).
The spelling of 4124453054034 in words is "four trillion, one hundred twenty-four billion, four hundred fifty-three million, fifty-four thousand, thirty-four".
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