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4125304125141 = 31375101375047
BaseRepresentation
bin111100000001111111010…
…010010111011011010101
3112121101010112111210020220
4330001333102113123111
51020042110324001031
612435045532144553
7604020611333163
oct74017722273325
915541115453226
104125304125141
1113505936a5491
12567618008159
1323c025b54c94
14103946cb2233
157249693d596
hex3c07f4976d5

4125304125141 has 4 divisors (see below), whose sum is σ = 5500405500192. Its totient is φ = 2750202750092.

The previous prime is 4125304125133. The next prime is 4125304125203. The reversal of 4125304125141 is 1415214035214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4125304125141 - 23 = 4125304125133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4125304175141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 687550687521 + ... + 687550687526.

It is an arithmetic number, because the mean of its divisors is an integer number (1375101375048).

Almost surely, 24125304125141 is an apocalyptic number.

It is an amenable number.

4125304125141 is a deficient number, since it is larger than the sum of its proper divisors (1375101375051).

4125304125141 is a wasteful number, since it uses less digits than its factorization.

4125304125141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1375101375050.

The product of its (nonzero) digits is 19200, while the sum is 33.

The spelling of 4125304125141 in words is "four trillion, one hundred twenty-five billion, three hundred four million, one hundred twenty-five thousand, one hundred forty-one".

Divisors: 1 3 1375101375047 4125304125141