41300113123131 has 4 divisors (see below), whose sum is σ = 55066817497512. Its totient is φ = 27533408748752.

The previous prime is 41300113123127. The next prime is 41300113123169. The reversal of 41300113123131 is 13132131100314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41300113123131 - 2² = 41300113123127 is a prime.

It is a super-2 number, since 2×41300113123131² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (41300113123121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6883352187186 + ... + 6883352187191.

It is an arithmetic number, because the mean of its divisors is an integer number (13766704374378).

Almost surely, 2^{41300113123131} is an apocalyptic number.

41300113123131 is a deficient number, since it is larger than the sum of its proper divisors (13766704374381).

41300113123131 is a wasteful number, since it uses less digits than its factorization.

41300113123131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13766704374380.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 41300113123131 its reverse (13132131100314), we get a palindrome (54432244223445).

The spelling of 41300113123131 in words is "forty-one trillion, three hundred billion, one hundred thirteen million, one hundred twenty-three thousand, one hundred thirty-one".