41300230132151 has 4 divisors (see below), whose sum is σ = 41471600381904. Its totient is φ = 41128859882400.

The previous prime is 41300230132129. The next prime is 41300230132201. The reversal of 41300230132151 is 15123103200314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41300230132151 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 41300230132151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41300230132121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85685124515 + ... + 85685124996.

It is an arithmetic number, because the mean of its divisors is an integer number (10367900095476).

Almost surely, 2^{41300230132151} is an apocalyptic number.

41300230132151 is a deficient number, since it is larger than the sum of its proper divisors (171370249753).

41300230132151 is a wasteful number, since it uses less digits than its factorization.

41300230132151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171370249752.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 41300230132151 its reverse (15123103200314), we get a palindrome (56423333332465).

The spelling of 41300230132151 in words is "forty-one trillion, three hundred billion, two hundred thirty million, one hundred thirty-two thousand, one hundred fifty-one".