Base | Representation |
---|---|
bin | 111100000110011000100… |
… | …100100110111101011011 |
3 | 112121211022102110222002000 |
4 | 330012120210212331123 |
5 | 1020131241431230201 |
6 | 12441150112412043 |
7 | 604245553603200 |
oct | 74063044467533 |
9 | 15554272428060 |
10 | 4130023305051 |
11 | 1352595539176 |
12 | 568514547023 |
13 | 23c5c876cb27 |
14 | 103c73953ca7 |
15 | 72670dc3d86 |
hex | 3c198926f5b |
4130023305051 has 48 divisors (see below), whose sum is σ = 7120130148000. Its totient is φ = 2359141376256.
The previous prime is 4130023304921. The next prime is 4130023305061. The reversal of 4130023305051 is 1505033200314.
4130023305051 is a `hidden beast` number, since 4 + 1 + 300 + 2 + 3 + 305 + 0 + 51 = 666.
It is not a de Polignac number, because 4130023305051 - 221 = 4130021207899 is a prime.
It is a super-2 number, since 2×41300233050512 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (4130023305061) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3013975 + ... + 4164623.
It is an arithmetic number, because the mean of its divisors is an integer number (148336044750).
Almost surely, 24130023305051 is an apocalyptic number.
4130023305051 is a deficient number, since it is larger than the sum of its proper divisors (2990106842949).
4130023305051 is a wasteful number, since it uses less digits than its factorization.
4130023305051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1153385 (or 1153372 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 4130023305051 its reverse (1505033200314), we get a palindrome (5635056505365).
The spelling of 4130023305051 in words is "four trillion, one hundred thirty billion, twenty-three million, three hundred five thousand, fifty-one".
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