41300333244041 has 4 divisors (see below), whose sum is σ = 41300427219012. Its totient is φ = 41300239269072.

The previous prime is 41300333243971. The next prime is 41300333244077. The reversal of 41300333244041 is 14044233300314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24935241990400 + 16365091253641 = 4993520^2 + 4045379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41300333244041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41300333243989 and 41300333244007.

It is not an unprimeable number, because it can be changed into a prime (41300333240041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46325150 + ... + 47208263.

It is an arithmetic number, because the mean of its divisors is an integer number (10325106804753).

Almost surely, 2^{41300333244041} is an apocalyptic number.

It is an amenable number.

41300333244041 is a deficient number, since it is larger than the sum of its proper divisors (93974971).

41300333244041 is an equidigital number, since it uses as much as digits as its factorization.

41300333244041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93974970.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 41300333244041 its reverse (14044233300314), we get a palindrome (55344566544355).

The spelling of 41300333244041 in words is "forty-one trillion, three hundred billion, three hundred thirty-three million, two hundred forty-four thousand, forty-one".