Base | Representation |
---|---|
bin | 101110111100111111111111… |
… | …0000111000001100001000001 |
3 | 2000011022210120111122002212002 |
4 | 1131321333332013001201001 |
5 | 413113124220002021040 |
6 | 4022215232404313345 |
7 | 152664361466431502 |
oct | 13571777607014101 |
9 | 2004283514562762 |
10 | 413004023470145 |
11 | 10a661028290028 |
12 | 3a3a2b439a2855 |
13 | 1495b15c954623 |
14 | 73db703b72ba9 |
15 | 32b32b0b24a15 |
hex | 1779ffe1c1841 |
413004023470145 has 16 divisors (see below), whose sum is σ = 517158167356800. Its totient is φ = 316034620602624.
The previous prime is 413004023470139. The next prime is 413004023470153. The reversal of 413004023470145 is 541074320400314.
It is a cyclic number.
It is not a de Polignac number, because 413004023470145 - 220 = 413004022421569 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413004023470099 and 413004023470108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7120595 + ... + 29609304.
It is an arithmetic number, because the mean of its divisors is an integer number (32322385459800).
Almost surely, 2413004023470145 is an apocalyptic number.
It is an amenable number.
413004023470145 is a deficient number, since it is larger than the sum of its proper divisors (104154143886655).
413004023470145 is a wasteful number, since it uses less digits than its factorization.
413004023470145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36827704.
The product of its (nonzero) digits is 161280, while the sum is 38.
Adding to 413004023470145 its reverse (541074320400314), we get a palindrome (954078343870459).
The spelling of 413004023470145 in words is "four hundred thirteen trillion, four billion, twenty-three million, four hundred seventy thousand, one hundred forty-five".
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