4130042343133 has 4 divisors (see below), whose sum is σ = 4720048392160. Its totient is φ = 3540036294108.

The previous prime is 4130042343107. The next prime is 4130042343197. The reversal of 4130042343133 is 3313432400314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4130042343133 - 2⁵ = 4130042343101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4130042343095 and 4130042343104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4130042943133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295003024503 + ... + 295003024516.

It is an arithmetic number, because the mean of its divisors is an integer number (1180012098040).

Almost surely, 2^{4130042343133} is an apocalyptic number.

It is an amenable number.

4130042343133 is a deficient number, since it is larger than the sum of its proper divisors (590006049027).

4130042343133 is an equidigital number, since it uses as much as digits as its factorization.

4130042343133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 590006049026.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 4130042343133 its reverse (3313432400314), we get a palindrome (7443474743447).

The spelling of 4130042343133 in words is "four trillion, one hundred thirty billion, forty-two million, three hundred forty-three thousand, one hundred thirty-three".