413004341401 has 4 divisors (see below), whose sum is σ = 413038016100. Its totient is φ = 412970666704.

The previous prime is 413004341371. The next prime is 413004341441. The reversal of 413004341401 is 104143400314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 340150234176 + 72854107225 = 583224^2 + 269915^2 .

It is a cyclic number.

It is not a de Polignac number, because 413004341401 - 2³¹ = 410856857753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413004341441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16818946 + ... + 16843483.

It is an arithmetic number, because the mean of its divisors is an integer number (103259504025).

Almost surely, 2^413004341401 is an apocalyptic number.

It is an amenable number.

413004341401 is a deficient number, since it is larger than the sum of its proper divisors (33674699).

413004341401 is a wasteful number, since it uses less digits than its factorization.

413004341401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33674698.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 413004341401 its reverse (104143400314), we get a palindrome (517147741715).

The spelling of 413004341401 in words is "four hundred thirteen billion, four million, three hundred forty-one thousand, four hundred one".