Base | Representation |
---|---|
bin | 101110111101000011110101… |
… | …1011111101100100001100111 |
3 | 2000011100120221101110112112020 |
4 | 1131322013223133230201213 |
5 | 413113243143040332010 |
6 | 4022223122022554223 |
7 | 152665103561242455 |
oct | 13572075337544147 |
9 | 2004316841415466 |
10 | 413012301105255 |
11 | 10a664595846885 |
12 | 3a3a4673b98973 |
13 | 1495bb7b864877 |
14 | 73dbc8b26b9d5 |
15 | 32b35e76b2470 |
hex | 177a1eb7ec867 |
413012301105255 has 16 divisors (see below), whose sum is σ = 663171353240544. Its totient is φ = 219489336765440.
The previous prime is 413012301105241. The next prime is 413012301105263. The reversal of 413012301105255 is 552501103210314.
It is not a de Polignac number, because 413012301105255 - 210 = 413012301104231 is a prime.
It is a super-5 number, since 5×4130123011052555 (a number of 74 digits) contains 55555 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48993151314 + ... + 48993159743.
It is an arithmetic number, because the mean of its divisors is an integer number (41448209577534).
Almost surely, 2413012301105255 is an apocalyptic number.
413012301105255 is a deficient number, since it is larger than the sum of its proper divisors (250159052135289).
413012301105255 is a wasteful number, since it uses less digits than its factorization.
413012301105255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97986311346.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 413012301105255 its reverse (552501103210314), we get a palindrome (965513404315569).
The spelling of 413012301105255 in words is "four hundred thirteen trillion, twelve billion, three hundred one million, one hundred five thousand, two hundred fifty-five".
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