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413013413101551 = 3137671137700517
BaseRepresentation
bin101110111101000100010110…
…1110001100111111111101111
32000011100200210212212210200020
41131322020231301213333233
5413113302432223222201
64022223424224533223
7152665143253121253
oct13572105561477757
92004320725783606
10413013413101551
1110a665006505089
123a3a4924481213
131495bcc8055942
1473dbd54c10263
1532b3660117a36
hex177a22dc67fef

413013413101551 has 4 divisors (see below), whose sum is σ = 550684550802072. Its totient is φ = 275342275401032.

The previous prime is 413013413101543. The next prime is 413013413101591. The reversal of 413013413101551 is 155101314310314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 413013413101551 - 23 = 413013413101543 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413013413101501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68835568850256 + ... + 68835568850261.

It is an arithmetic number, because the mean of its divisors is an integer number (137671137700518).

Almost surely, 2413013413101551 is an apocalyptic number.

413013413101551 is a deficient number, since it is larger than the sum of its proper divisors (137671137700521).

413013413101551 is a wasteful number, since it uses less digits than its factorization.

413013413101551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137671137700520.

The product of its (nonzero) digits is 10800, while the sum is 33.

Adding to 413013413101551 its reverse (155101314310314), we get a palindrome (568114727411865).

The spelling of 413013413101551 in words is "four hundred thirteen trillion, thirteen billion, four hundred thirteen million, one hundred one thousand, five hundred fifty-one".

Divisors: 1 3 137671137700517 413013413101551