Base | Representation |
---|---|
bin | 111100000110101010011… |
… | …000011110000111101001 |
3 | 112121212002020201222112010 |
4 | 330012222120132013221 |
5 | 1020132344430104001 |
6 | 12441235505110133 |
7 | 604256142456330 |
oct | 74065230360751 |
9 | 15555066658463 |
10 | 4130322113001 |
11 | 1352729178a97 |
12 | 568598628349 |
13 | 23c645641176 |
14 | 103ca14d6d17 |
15 | 7268c2498d6 |
hex | 3c1aa61e1e9 |
4130322113001 has 32 divisors (see below), whose sum is σ = 6353266295808. Its totient is φ = 2337897585600.
The previous prime is 4130322112997. The next prime is 4130322113041. The reversal of 4130322113001 is 1003112230314.
4130322113001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4130322113001 - 22 = 4130322112997 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (4130322113041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24369651 + ... + 24538551.
It is an arithmetic number, because the mean of its divisors is an integer number (198539571744).
Almost surely, 24130322113001 is an apocalyptic number.
It is an amenable number.
4130322113001 is a deficient number, since it is larger than the sum of its proper divisors (2222944182807).
4130322113001 is a wasteful number, since it uses less digits than its factorization.
4130322113001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 179901.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 4130322113001 its reverse (1003112230314), we get a palindrome (5133434343315).
The spelling of 4130322113001 in words is "four trillion, one hundred thirty billion, three hundred twenty-two million, one hundred thirteen thousand, one".
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