4131003100101 has 4 divisors (see below), whose sum is σ = 5508004133472. Its totient is φ = 2754002066732.

The previous prime is 4131003100043. The next prime is 4131003100109. The reversal of 4131003100101 is 1010013001314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4131003100101 - 2⁷ = 4131003099973 is a prime.

It is a super-2 number, since 2×4131003100101² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4131003100109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 688500516681 + ... + 688500516686.

It is an arithmetic number, because the mean of its divisors is an integer number (1377001033368).

Almost surely, 2^{4131003100101} is an apocalyptic number.

It is an amenable number.

4131003100101 is a deficient number, since it is larger than the sum of its proper divisors (1377001033371).

4131003100101 is a wasteful number, since it uses less digits than its factorization.

4131003100101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1377001033370.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 4131003100101 its reverse (1010013001314), we get a palindrome (5141016101415).

The spelling of 4131003100101 in words is "four trillion, one hundred thirty-one billion, three million, one hundred thousand, one hundred one".