Base | Representation |
---|---|
bin | 101110111101110001010111… |
… | …0000110111011010110010011 |
3 | 2000011200221021001111202220012 |
4 | 1131323202232012323112103 |
5 | 413121343343143400003 |
6 | 4022340050045505135 |
7 | 153005134166411222 |
oct | 13573425606732623 |
9 | 2004627231452805 |
10 | 413110055450003 |
11 | 10a6a1a995a994a |
12 | 3a3bb5b58721ab |
13 | 1496815a049002 |
14 | 74028c1d68cb9 |
15 | 32b5e196b28d8 |
hex | 177b8ae1bb593 |
413110055450003 has 16 divisors (see below), whose sum is σ = 438616586459520. Its totient is φ = 387738993248256.
The previous prime is 413110055449907. The next prime is 413110055450021. The reversal of 413110055450003 is 300054550011314.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413110055450003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413110055450033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14094950 + ... + 32013867.
It is an arithmetic number, because the mean of its divisors is an integer number (27413536653720).
Almost surely, 2413110055450003 is an apocalyptic number.
413110055450003 is a deficient number, since it is larger than the sum of its proper divisors (25506531009517).
413110055450003 is a wasteful number, since it uses less digits than its factorization.
413110055450003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46110286.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 413110055450003 in words is "four hundred thirteen trillion, one hundred ten billion, fifty-five million, four hundred fifty thousand, three".
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