Base | Representation |
---|---|
bin | 111100000111011011111… |
… | …011010001100010100111 |
3 | 112121221020011210200022100 |
4 | 330013123323101202213 |
5 | 1020141100222220403 |
6 | 12441454200503143 |
7 | 604315554556545 |
oct | 74073373214247 |
9 | 15557204720270 |
10 | 4131153320103 |
11 | 1353015394207 |
12 | 56878aa7aab3 |
13 | 23c7488cc5a4 |
14 | 103d3da66d95 |
15 | 726da1d82a3 |
hex | 3c1dbed18a7 |
4131153320103 has 12 divisors (see below), whose sum is σ = 5969314526968. Its totient is φ = 2753136183600.
The previous prime is 4131153320101. The next prime is 4131153320113. The reversal of 4131153320103 is 3010233511314.
4131153320103 is a `hidden beast` number, since 4 + 1 + 3 + 1 + 1 + 533 + 20 + 103 = 666.
4131153320103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4131153320103 - 21 = 4131153320101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4131153320101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 80475400 + ... + 80526717.
Almost surely, 24131153320103 is an apocalyptic number.
4131153320103 is a deficient number, since it is larger than the sum of its proper divisors (1838161206865).
4131153320103 is a wasteful number, since it uses less digits than its factorization.
4131153320103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161004974 (or 161004971 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 27.
Adding to 4131153320103 its reverse (3010233511314), we get a palindrome (7141386831417).
The spelling of 4131153320103 in words is "four trillion, one hundred thirty-one billion, one hundred fifty-three million, three hundred twenty thousand, one hundred three".
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