413140025113 has 4 divisors (see below), whose sum is σ = 420142398480. Its totient is φ = 406137651748.

The previous prime is 413140025071. The next prime is 413140025141. The reversal of 413140025113 is 311520041314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413140025113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413140025173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3501186595 + ... + 3501186712.

It is an arithmetic number, because the mean of its divisors is an integer number (105035599620).

Almost surely, 2^413140025113 is an apocalyptic number.

It is an amenable number.

413140025113 is a deficient number, since it is larger than the sum of its proper divisors (7002373367).

413140025113 is an equidigital number, since it uses as much as digits as its factorization.

413140025113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7002373366.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 413140025113 its reverse (311520041314), we get a palindrome (724660066427).

The spelling of 413140025113 in words is "four hundred thirteen billion, one hundred forty million, twenty-five thousand, one hundred thirteen".