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41314045241114 = 220657022620557
BaseRepresentation
bin10010110010011001011001…
…11111011010011100011010
312102021120202211212122020222
421121030230333122130122
520403342131040203424
6223511224350120042
711462561361231062
oct1131145477323432
9172246684778228
1041314045241114
1112189208535848
124772b321b0022
131a08b89481059
14a2b8791563a2
154b9a16c0ee5e
hex25932cfda71a

41314045241114 has 4 divisors (see below), whose sum is σ = 61971067861674. Its totient is φ = 20657022620556.

The previous prime is 41314045241113. The next prime is 41314045241143. The reversal of 41314045241114 is 41114254041314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 32514913774225 + 8799131466889 = 5702185^2 + 2966333^2 .

It is not an unprimeable number, because it can be changed into a prime (41314045241111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10328511310277 + ... + 10328511310280.

Almost surely, 241314045241114 is an apocalyptic number.

41314045241114 is a deficient number, since it is larger than the sum of its proper divisors (20657022620560).

41314045241114 is a wasteful number, since it uses less digits than its factorization.

41314045241114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20657022620559.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 41314045241114 its reverse (41114254041314), we get a palindrome (82428299282428).

The spelling of 41314045241114 in words is "forty-one trillion, three hundred fourteen billion, forty-five million, two hundred forty-one thousand, one hundred fourteen".

Divisors: 1 2 20657022620557 41314045241114