Base | Representation |
---|---|
bin | 1100000001101010110… |
… | …11010011101011000101 |
3 | 1110111120112120001102100 |
4 | 12000311123103223011 |
5 | 23232230040230313 |
6 | 513454425102313 |
7 | 41565544226016 |
oct | 6006533235305 |
9 | 1414515501370 |
10 | 413213211333 |
11 | 14a2740a366a |
12 | 68100327999 |
13 | 2cc72c417a0 |
14 | 15ddcd8d00d |
15 | ab36914173 |
hex | 60356d3ac5 |
413213211333 has 12 divisors (see below), whose sum is σ = 642776106700. Its totient is φ = 254285053056.
The previous prime is 413213211317. The next prime is 413213211349. The reversal of 413213211333 is 333112312314.
413213211333 is a `hidden beast` number, since 4 + 1 + 3 + 2 + 1 + 321 + 1 + 333 = 666.
It is an interprime number because it is at equal distance from previous prime (413213211317) and next prime (413213211349).
It can be written as a sum of positive squares in 2 ways, for example, as 175164849729 + 238048361604 = 418527^2 + 487902^2 .
It is not a de Polignac number, because 413213211333 - 24 = 413213211317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413213211297 and 413213211306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (413213211233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1765868308 + ... + 1765868541.
Almost surely, 2413213211333 is an apocalyptic number.
It is an amenable number.
413213211333 is a deficient number, since it is larger than the sum of its proper divisors (229562895367).
413213211333 is a wasteful number, since it uses less digits than its factorization.
413213211333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3531736868 (or 3531736865 counting only the distinct ones).
The product of its digits is 3888, while the sum is 27.
Adding to 413213211333 its reverse (333112312314), we get a palindrome (746325523647).
The spelling of 413213211333 in words is "four hundred thirteen billion, two hundred thirteen million, two hundred eleven thousand, three hundred thirty-three".
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