41324411122033 has 4 divisors (see below), whose sum is σ = 44503211977588. Its totient is φ = 38145610266480.

The previous prime is 41324411121971. The next prime is 41324411122097. The reversal of 41324411122033 is 33022111442314.

It is a happy number.

41324411122033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6874003036224 + 34450408085809 = 2621832^2 + 5869447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41324411122033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41324411121986 and 41324411122004.

It is not an unprimeable number, because it can be changed into a prime (41324411129033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1589400427758 + ... + 1589400427783.

It is an arithmetic number, because the mean of its divisors is an integer number (11125802994397).

Almost surely, 2^{41324411122033} is an apocalyptic number.

It is an amenable number.

41324411122033 is a deficient number, since it is larger than the sum of its proper divisors (3178800855555).

41324411122033 is a wasteful number, since it uses less digits than its factorization.

41324411122033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3178800855554.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 41324411122033 its reverse (33022111442314), we get a palindrome (74346522564347).

The spelling of 41324411122033 in words is "forty-one trillion, three hundred twenty-four billion, four hundred eleven million, one hundred twenty-two thousand, thirty-three".